In the circuit shown in figure potential difference between the points `A` and `B` in the steady state is

Options

A. 25
B. 75
C. 100
D. none of the above

Answer

1

Explanation

The circuit can be redrawn after reducing the equipotential points and dropping resistances as they do not produce a potential drop in the steady state.

Potential difference between A and C is 100 volt. This is divided in the inverse ratio of equivalent capacitances. ltb rgt `therefore V_(AB)=(100V)/((6+2)muF)xx2muF=25V`
`therefore V_(BC)=(100V)/((6+2)muFxx6muF)=75V`