See the electrical circuit shown in this figure. Which of the following equations is the correct equation for it ?

Options

A. `epsilon_(1)-(i_(1)+i_(2))R+i_(1)r_(1)=0`
B. `epsilon_(1)-(i_(1)+i_(2))R-i_(1)r_(1)=0`
C. `epsilon_(2)-i_(2)r_(2)-epsilon_(1)-i_(1)r_(1)=0`
D. `-epsilon_(2)-(i_(1)+i_(2))R+i_(2)r_(2)=0`

Answer

2

Explanation

` epsilon_(2)=i_(2)r_(2)+(i_(1)+i_(2))R`
`epsilon_(1)=i_(1)r_(1)+(i_(1)+i_(2))R`
` epsilon_(2)-epsilon_(1)=i_(2)r_(2)-i_(1)r_(1)`