In a potentiometer arrangment, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm`, what is the emf of the second cell ?

Options

A. 3.25V
B. 2.5V
C. 2.25V
D. 2V

Answer

3

Explanation

Here `I_(1)=35cm, L_(2)=63cm`
`epsilon_(1)=1.25Vepsilon_(2)`=?
As `(epsilon_(1))/(epsilon_(2))=(l_(1))/(l_(2)) therefore epsilon_(2)=(l_(2))/(l_(1)) xxepsilon_(1)=(63cm)/(35cm)xx1.25V`
=2.25V