The thermo emf of a thermocouple is given by `E=alpha(theta-theta_(g))+beta(theta^(2)-theta_(0)^(2))` Determine the neutral temperature and inversion temperature.

Explanation

At neutral temperature `(dE)/(dtheta)=0rArr alpha+beta(2theta_(n))=0=-(alpha)/(2beta)`
At inversion temperature `E=0rArr alpha(theta_(1)-theta_(0))+beta(theta_(1)^(2)-theta_(0)^(2))=0 rArr theta_(1)=-theta_(0)-(alpha)/(beta)`