The coil of a 1 000W electric heater is cut into two equal parts. If the two parts are used separately as heaters, their combined wattage will

Options

A. 500W
B. 1000W
C. 2000W
D. 4000W

Explanation

Power `=(V^(2))/(R)` where R denotes the resistance of the coil
`therefore R=(V^(2))/(P)=(V^(2))/(1000)Omega`
Resistance of each part `=(R)/(2)=(V^(2))/(2000)Omega`
`therefore` power of each part `=(V^(2)xx2000)/(V^(2))` =2000W
`therefore` combined wattage `=2xx200=4000` W