Two resistance connected in parallel across a cell of negligible internal resistance, use 4.5 times the power that they would use, when in series across the same cell. If one of the resistance is 8ohm, the other is:-

Options

A. `8Omega`
B. `12Omega`
C. `16Omega`
D. `36Omega`

Explanation

To solve the problem, we need to find the value of the second resistance \( R_2 \) given that one resistance \( R_1 = 8 \, \Omega \) and the power used in parallel is 4.5 times the power used in series.

### Step-by-Step Solution:

1. **Understanding Power in Series and Parallel:**
- The power \( P_s \) in series is given by:
\[
P_s = \frac{V^2}{R_1 + R_2}
...