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A TV tower stands vertically on a bank ...

A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is `60^@`. From another point 20 m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower and the width of the canal.

Text Solution

Verified by Experts

Tan`30^0=(AB)/(BD)`
AB=BDtan`30^0`
tan`60^0=(AB)/(BC)`
Tan`60^0`=BDtan`30^0`/(BC)
`sqrt3=(BD)/(sqrt3BC)`
BD=3BC
3BC=BC+20m
2BC=20m
...
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