`(8x)/(9)+3=(5x)/(6)+1`

x+7-(8x)/(3)=(17)/(6)-(5x)/(2)

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

Solve : (7x +3)/(4) + (9x -5)/(8) = (16x-3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order (A) x = (-5)/(30) = (-1)/(6) (B) (7x + 3)/(4) + (9x -5)/(8) = (16x-3)/(16) rArr (14x + 6 + 9x -5)/(8) = (16x -3)/(16) (C) (23x + 1)/(8) = (16x -3)/(16) rArr 23x + 1 = (16x -3)/(2) (D) 46x + 2 = 16x - 3 rArr 30 x = -5

X+7-(8X)/(3)=(17)/(6)-(5X)/(2)

(x-1)/(3)+(2x+5)/(6)=(3x-6)/(9)-(2x-5)/(2)

Fill in the blanks from the given options : (1)/(2) , 9 (6x - 9) (3x^(2) - 9x + 5)^(8), 49, -2, (1)/(2) [log(sin x)]^(2) + c, (1)/(x), 10 , onto (d)/(dx) [3x^(2) - 9x+5]^(9) = ………

Check whether the following are quadratic equations : (1) (x-3)^(2)=x(2x-5) (2) (2x-3)(8x+1) = (4x+5)(4x-5) (3) (5x+3)(x-2)=(4x+3)(2x-1) (4) (2x+5)^(3)=8(x-1)^(3) (5) x^(2)+7x-8=x(x+5) (6) x^(3)+9x^(2)-7x+2=(x+3)^(3)