The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m.

Explanation

To solve the problem step by step, we will use trigonometric concepts involving right triangles.

### Step 1: Set Up the Problem
Let the height of the tower be \( H \). We have two points, \( C \) and \( D \), which are 4 m and 9 m away from the base of the tower respectively. The angles of elevation from these points are complementary, meaning if one angle is \( \theta \), the other angle is \( 90^\circ - \theta \).

### Step 2: Analyze Triangle \( ABC \)
In triangle \( ABC \):
- \( BC = 4 \) m (distance from point \( C \) to the base of the tower)
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