Tangents are drawn from the origin to the curve `y = sin x`. Prove that their points of contact lie on the curve `x^(2) y^(2) = (x^(2) - y^(2))`

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^2y^2=(x^2-y^2) .

If tangents are drawn from the origin to the curve y= sin x , then their points of contact lie on-

Tangents are drawn from origin to the curve y = sin+cos x ·Then their points of contact lie on the curve

Tangents are drawn from origin to the curve y = sin+cos x ·Then their points of contact lie on the curve

Tangents are drawn from origin to the curve y=sin+cos x Then their points of contact lie on the curve

3.(1) x + y = 0(2) x - y = 0If tangents are drawn from the origin to the curve y = sin x, then their points of contact lie on the curve(3) x2 - y2 = x2y2 (4) x2 + y2 = x2y2(2) x + y = xy(1) X- y = xy

Tangents are drawn from the origin to curve y=sinxdot Prove that points of contact lie on y^2=(x^2)/(1+x^2)