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If pressure at half the depth of a lake ...

If pressure at half the depth of a lake is equal to 2//3 pressure at the bottom of the lake then what is the depth of the lake ?

A

`10 m`

B

`20 m`

C

`60 m`

D

`30 m`

Text Solution

Verified by Experts

The correct Answer is:
B
Pressure at bottom of the lake = `P_(0) + hrhog` and pressure ay half the depth of a lake
`= P_(0) + (h)/(2) rhog`
According to given condition `P_(0) + (1)/(2) hrhog = (2)/(3) (P_(0)+hrhog) implies (1)/(3) P_(0) = (1)/(6)hrhog implies`
`h=(2P_(0))/(rhog) = (2xx10^(5))/(10^(3)xx10)=20 m`
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