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Density of ice is rho and that of water ...

Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?

A

`(M)/(sigma-rho)`

B

`(sigma-rho)/(M)`

C

`M[(1)/(rho)-(1)/(sigma)]`

D

`(1)/(M)[(1)/(rho)-(1)/(sigma)]`

Text Solution

Verified by Experts

The correct Answer is:
C
Volume of ice =`(M)/(rho)`, volume of water =`(M)/(sigma)`
`therefore "Change in volume" =(M)/(rho)-(m)/(sigma)=M((1)/(rho)-(1)/(sigma))`
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