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Two substances of densities rho(1) and r...

Two substances of densities `rho_(1)` and `rho_(2)` are mixed in equal volume and the relative density of mixture is `4`. When they are mixed in equal masses, the relative density of the mixture is 3. the values of `rho_(1)` and `rho_(2)` are:

A

`rho_(1)=6` and `rho_(2)=2`

B

`rho_(1)=3` and `rho_(2)=5`

C

`rho_(1)=12` and `rho_(2)=4`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
When substances are mixed in equal volume then density
`=(rho_(1)+rho_(2))/(2)=4 implies rho_(1)+rho_(2) = 8 " "…..(i)`
When substance are mixed in equal masses then density
`=(2rho_(1)rho_(2))/(rho_(1)+rho_(2)) = 3 implies 2rho_(1)rho_(2) = 3(rho_(1)+rho_(2))" "……(ii)`
By solving (i) and (ii) we get `rho_(1) =6` and `rho_(2) =2`.
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