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The fraction of a floating object of vol...

The fraction of a floating object of volume `V_(0)` and density `d_(0)` above the surface of a liquid of density d will be

A

`(d_(0))/(d)`

B

`(dd_(0))/(d+d_(0))`

C

`(d-d_(0))/(d)`

D

`(dd_(0))/(d-d_(0))`

Text Solution

Verified by Experts

The correct Answer is:
C
For the floatation `V_(0)d_(0)g = V_("in") d g implies V_("in") = V_(0) (d_(0))/(d)`
`therefore V_("out") = V_(0) - V_("in") = V_(0) - V_(0) (d_(0))/(d) = V_(0) [(d-d_(0))/(d)] implies (V_("out"))/(V_(0)) = (d-d_(0))/(d)`.
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