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A square plate of 0.1 m side moves paral...

A square plate of 0.1 m side moves parallel to a second plate with a velocity of `0.1 m//s`, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise , distance between the plates in m is

A

`0.1`

B

`0.05`

C

`0.005`

D

`0.0005`

Text Solution

Verified by Experts

The correct Answer is:
D
`A=(0.1)^(2) = 0.01m^(2),.^ (eta=0.01 "Poise" = 0.001 "decapoise") (M.K.S. "unit")`,
`dupsilon = 0.1m//s` and `F = 0.002N`
`F=etaA(dv)/(dx) " "therefore dx = (etaAdv)/(F) = (0.001xx0.01xx0.01)/(0.002) = 0.0005m`.
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