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Two soap bubbles of radii r(1) and r(2) ...

Two soap bubbles of radii `r_(1)` and `r_(2)` equal to 4 cm and 5 cm are touching each other over a common surface `S_(1)S_(2)` (shown in figure). Its radius will be

A

`4cm`

B

`20cm`

C

`5cm`

D

`4.5cm`

Text Solution

Verified by Experts

The correct Answer is:
B
Radius of curvature of common surface of double bubble
`r=(r_(2)r_(1))/(r_(2)-r_(1)) = (5xx4)/(5-4) = 20cm`
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