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A large open tank has two holes in the w...

A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal to

A

`(L)/sqrt(2pi)`

B

`2 pi L`

C

`L`

D

`(L)/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume flowing per sec `V=av`
`L^(2)sqrt(2gy)=pir^(2)sqrt(2g(4y))" "impliesL^(2)=2piR^(2)`
`R=(L)/sqrt(2pi)`
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Knowledge Check

  • A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities or water flowing out per second from the two holes are the same. Then, the value of R is

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