Consider a horizontally oriented syringe containing water located of a height of `1.25 m` above the ground. The diameter of plunger is `8 mm` and the diameter if the nozzle is `2 mm`. The plunger is pushed with a constant speed of `0.25 m//s`. Find the horizontal range of water stream on the ground. Take `g = 10 m//s^2`.
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Answer

x=2m

Explanation

From equation of continuity
`a_(1)v_(1)=a_(2)v_(2)`
`pi(4xx10^(-3))^(2)xx0.25=pi(1xx10^(-3))xxv_(2)" "impliesv_(2)=4m//s`
`x = v_(2)t`
`x=v_(2)sqrt ((2h)/(g))=4sqrt((2xx1.25)/(10))=2m`