`15.0 g` of an unknown molecular material was dissolved in `450 g` of water. The reusulting solution was found to freeze at `-0.34 .^(@)C`. What is the the molar mass of this material. (`K_(f)` for water `= 1.86 K kg mol^(-1)`)

15.0 g of an unknown molecular material was dissolved in 450 g of water. The resulting solution was found to freeze at -0.34 ^(@)C . What is the the molar mass of this material. ( K_(f) for water = 1.86 K kg mol^(-1) )

(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) 15.0 g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at -0.34^(@)C . What is the molar mass of the material ? (K_(f) for water = 1.86 K kg mol^(-1))

(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) 15.0 g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at -0.34^(@)C . What is the molar mass of the material ? (K_(f) for water = 1.86 K kg mol^(-1))

15.0g of an unknown molecular material is dissolved in 450g of water. The resulting solution freezes at -0.34^(@)C. What is the molar mass of the material? K_(f) for water = 1.86K kg mol^(-1).

15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0 . 34^(@) C . What is them molar ass of the substance ? ( K_(f) for water = 1. 86 K kg mol^(-1) )

15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0.34^(@) C. what is molar mass of the substance ? (K_(f)" for water " = 1.86 k kg " mol"^(-1))