A body of mass 1kg lies on smooth inclined plane. The block of mass `m` is given force `F=10` `N` horizontally as shown. The magnitude of net normal reaction on the block is:

A block of mass 3kg is at rest on a rough inclined plan as shown in the Figure. The magnitude of net force exerted by the surface on the block will be

A block of mass 3kg is at rest on a rough inclined plan as shown in the Figure. The magnitude of net force exerted by the surface on the block will be

A block of mass 3kg is at rest on a rough inclined plan as shown in the Figure. The magnitude of net force exerted by the surface on the block will be

A horizontal force acting on a block of mass m which is placed on an inclined plane (as shown in the figure). What is the normal reaction N on the block?

A horizontal force F is applied to a block of mass m on a smooth fixed inclined plane of inclination theta to the horizontal as shown in the figure. Resultant force on the block up the plane is:

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in figure. The block remains stationary if (take g=10m//s^2 )

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in the figure. The block remains stationary if ( take g=10 m//s^(2))

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in the figure. The block remains stationary if ( take g=10 m//s^(2))

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in figure. The block remains stationary if (take g=10m//s^2 )