`37/13=2+1/(x+1/(y+1/z))` where `x, y, z` are natural numbers, then find value of `x + y +z` (i)`6` (ii)`7` (iii)`8` (iv)`9`

If (37)/(13)=2+1/(x+1/(y+1/z)) where x,y,z are natural numbers, then what is z equal to?

If 36/11 = 3 + 1/(x + 1/(y + 1/z)) , where x, y and z are natural numbers, then what is (x+y+z) equal to ?

If (61)/(19) =3+(1)/(x+(1)/(y+(1)/(z))) where x, y and z are natural numbers, then what is z equal to?

If (37)/(13)=2-:1/(x+1/(y+1/z)) , where x , y , z are natural numbers, then x , y , z are (a) 1, 2, 5 (b) 1, 5, 2 (c) 5, 2, 11 (d) 11, 2, 5

if (30)/(7)=x+(1)/(y+(1)/(z)) where x,y,z are positive integers then value of (x+y+z) equals

The system of equations 3x+y+2z=6,xyz=-5,3xy+2yz+6xz=-1 has a solution (x,y,z), where x,y,z are integers.Then the value of (x+z)/(y) is equal to (i)0(ii)1(iii)2(iv)3

If xyz=(1-x)(1-y)(1-z) Where 0<=x,y, z<=1 , then the minimum value of x(1-z)+y (1-x)+ z(1-y) is

If x,y,z are distinct real numbers then the value of ((1)/(x-y))^(2)+((1)/(y-z))^(2)+((1)/(z-x))^(2) is