In `triangleABC`, If `(b+c)/(11)=(c+a)/(12)=(a+b)/(13)`, then `cosC=`

In a triangle ABC , if (b+c)/(11)=(c+a)/(12)=(a+b)/(13) , then cos A=

In a triangle ABC, if (b+c)/(11) =(c+a)/(12) =(a+b)/(13), then the value of cos C is-

In a DeltaABCV if (b+c)/(11)=(c+a)/(12)=(a+b)/(13) then cos C=

With usual notations, if in a triangle ABC (b+c)/(11) = (c+a)/(12) = (a+b)/(13) , then cos A : cos B : cos C is :

With usual notations, if in a triangle ABC (b+c)/(11) = (c+a)/(12) = (a+b)/(13) , then cos A : cos B : cos C is :

With usual notations, if in a triangleABC (b+c)/(11)=(c+a)/(12)=(a+b)/(13) , then prove that: (cosA)/7=(cosB)/(19)=(cosC)/(25)

With usual notion, if in triangle A B C , (b+c)/(11)=(c+a)/(12)=(a+b)/(13),t h e np rov et h a t (cosA)/7=(cosB)/(19)=(cosC)/(25)

With usual notion, if in triangle A B C , (b+c)/(11)=(c+a)/(12)=(a+b)/(13),t h e np rov et h a t (cosA)/7=(cosB)/(19)=(cosC)/(25)

With usual notation , if in triangle ABC, (b + c)/11 = (c + a)/12 = (a + b)/13 , then cos A : cos B : cos C =

With usual notion,if in triangle ABC ,(b+c)/(11)=(c+a)/(12)=(a+b)/(13), then prove that (cos A)/(7)=(cos B)/(19)=(cos C)/(25)