Home
Class 12
PHYSICS
In a Young's double slit experiment, the...

In a Young's double slit experiment, the fringe width is found to be `0.4mm`. If the whole apparatus is immersed in water of refractive index `4//3` without disturbing the geometrical arrangement, the new fringe width will be

Text Solution

Verified by Experts

The correct Answer is:
`0.30 mm`
`AS beta=(lambdaD)/(d)=0.4 mm`
`rArr` by changing `mu, lambda` becomes `(lambda)/(mu) rArr beta=(3)/(4)xx0.4=0.3 mm.`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    RESONANCE|Exercise Exercise-1 (Part-2)|13 Videos

  • WAVE OPTICS

    RESONANCE|Exercise Exercise-2 (Part-1)|10 Videos

  • WAVE OPTICS

    RESONANCE|Exercise Advanced Level Problems|8 Videos

  • WAVE ON STRING

    RESONANCE|Exercise Exercise- 3 PART I|19 Videos

Similar Questions

Explore conceptually related problems

In Young's double slit experiment, the fringe width is found to be 0.6 mm. without distrubing anything, the whole arrangment is dipped in water of refractive index 4/3 the new fringe width will be

In Young's double slit experiment the fringe width is 4mm .If the experiment is shifted to water of refractive index 4/3 the fringe width becomes (in mm)

In the Young’s double slit experiment, for which colour the fringe width is least

In Young's double slit experiment, for which colour is the fringe width maximum?

In Youngs 's double slit experiment, the fringe width obtained by using monochromatic light of wavelength 6000 Å is 2 mm. if the whole apparatus is immersed in water of R.I. 1.33, then the change in fringe width will be

In a Young's double-slit experment, the fringe width is beta . If the entire arrangement is now placed inside a liquid of refractive index mu , the fringe width will become