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A source emiting two light waves of wavelength `580 nm` and `700 nm` is used in a young's double slit interference experiment. The swparation between the slits is `0.20 mm` and the interference is observed on a screen placed at `150 cm` from the slits. Find the linear separation between the frist maximum (next to the central maximum) corresponding to the two wavelenghts.

Text Solution

Verified by Experts

The correct Answer is:
`0.9 mm`
As `lambda lt lt d`
`rArr beta_(1)=(lambda_(1)D)/(d) beta_(2)=(lambda_(2)D)/(d)`
So, `beta_(2)-beta_(1)=((lambda_(2)-lambda_(1))D)/(d) = ((700-580)xx10^(-9)xx1.5)/(0.20xx10^(-3)) =0.9 mm.`
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