Home
Class 12
PHYSICS
If the first minima in Young's double-sl...

If the first minima in Young's double-slit experiment occurs directly in front of one of the slits (distance between slit and screen `D = 12 cm` and distance between slits `d = 5 cm)`, then the wavelength of the radiation used can be

A

`2 cm` only

B

`4 cm` ony

C

`2m,(2)/(3) cm,(2)/(5) cm`

D

`4cm,(4)/(3) cm,(4)/(5) cm`

Text Solution

Verified by Experts

The correct Answer is:
A

Notice that `d` is not very small than `D,` so we can not use `Delta=d sintheta`.
`S_(1)P-S_(2)=DeltaP=(lambda)/(2)` {`therefore` first minima}
`rArr sqrt(5^(2)+12^(2)) -(12) =(lambda)/(2) "get" lambda=2 cm`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    RESONANCE|Exercise Exercise-2 (Part-2)|5 Videos
  • WAVE OPTICS

    RESONANCE|Exercise Exercise-2 (Part-3)|5 Videos
  • WAVE OPTICS

    RESONANCE|Exercise Exercise-1 (Part-2)|13 Videos
  • WAVE ON STRING

    RESONANCE|Exercise Exercise- 3 PART I|19 Videos

Similar Questions

Explore conceptually related problems

How does the fringe width, in Young's double-slit experiment, change when the distance of separation between the slits and screen is doubled ?

In Young's double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be

When the distance between the slit and screen in Young's experiment is doubled then

In Young's double slit experiment, the distance between the two slits is 0.1 mm, the distance between the screen and the slit is 100 cm. if the width of the fringe is 5 mm, then the wavelength of monochromatic light used is

In Young's double slit experiment, the sepcaration between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is