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A parallel beam of light (lambda= 5000 Å...

A parallel beam of light `(lambda= 5000 Å)` is incident at an angle `theta=30^@` with the normal to the slit plane in a Young's double slit experiment. The intensity due to each slit is `I_0`. Point O is equidistant from `S_1 and S_2`. The distance between slits is 1mm.

A

the intensity at `O` is `4I_(0)`

B

the intensity at `O` is zero

C

the intensity at a point on the screen `4m` from `O` is `4I_(0)`

D

the intensity at a point on the screen `4m` from `O` is zero

Text Solution

Verified by Experts

The correct Answer is:
A, C
As `d ltlt D, rArr` path difference `= d sin theta (at 0) = 1mmxxsin 30^(@)=0.5 mm`
if it is a maxima `rArr 10^(-3)xx0.5 =(5000xx10^(-10))mxx(n)`
`n` must be integer. `"get" n=1000.`
Hence `O` is a maxima of intensity `4I_(0)`

Now path difference at `Q=d sin theta` only `QS_(1) approx QS_(2).`
`d sin theta =1xx1//2=0.5 mm =` integer multiple of `lambda.` Hence maxima.
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