Home
Class 12
PHYSICS
Two waves passing through a region are r...

Two waves passing through a region are respresented by
`y_(1) = 5 mm sin [(2pi cm^(-1))x - (50 pis^(-1))t]`
and `y_(2) = 10 mm sin [(pi cm^(-1))x - (100 pis^(-1))t]`
Find the displacement of the particle at `x = 1 cm` at time `t = 5.0 ms`.

Text Solution

Verified by Experts

Accoding to the principle of superposition, each wave produce its disturbance independent of the other and the resultant disturbance is equal to the vector sum of the individual disturbance. The displacements of the particle at `x = 1cm` at time `t = 5.0 ms` due to the two waves are.
`y_(1) = 2 mm [(2pi cm^(-1)) xx - (50 pi s^(-1))t]`
`y_(1) = 5 mm sin[(2pi cm^(-1)) xx 1 cm - (50 pi s^(-1))5 xx 10^(-3) sec]`
`= 5 mm sin [2pi - (p)/(4)] = -5 mm`
and `y_(2) = 10 mm sin [(pi cm^(-1)) xx - (100 pi s^(-1))t]`,
`y_(2) = 10 mm sin [(pi cm^(-1)) xx 1 cm - (100 pi s^(-1))5 xx 10^(-3) sec]`
`= 10 mm sin [pi - (pi)/(2)] = 10 mm`
The net displacement is : `y = y_(1) + y_(2) = 10 mm - 5 mm = 5 mm`
Promotional Banner

Topper's Solved these Questions

  • TRAVELLING WAVES

    RESONANCE|Exercise Solved Miscellaneous Problems|7 Videos
  • TRAVELLING WAVES

    RESONANCE|Exercise Board Level Exercise|27 Videos
  • TEST SERIES

    RESONANCE|Exercise PHYSICS|127 Videos
  • WAVE ON STRING

    RESONANCE|Exercise Exercise- 3 PART I|19 Videos

Similar Questions

Explore conceptually related problems

Two waves passing through a region are represented by y=(1.0cm) sin [(3.14 cm^(-1))x - (157s^(-1) x - (157s^(-1))t] and y = (1.5 cm) sin [(1.57 cm^(-1))x- (314 s^(-1))t]. Find the displacement of the particle at x = 4.5 cm at time t = 5.0 ms.

If two SHMs are represented by equations y_(1) = 5 sin (2pi t + pi//6) and y_(2) = 5 [sin (3pi) + sqrt3 cos (3pi t)] . Find the ratio of their amplitudes.

Two waves travelling in a medium in the x-direction are represented by y_(1) = A sin (alpha t - beta x) and y_(2) = A cos (beta x + alpha t - (pi)/(4)) , where y_(1) and y_(2) are the displacements of the particles of the medium t is time and alpha and beta constants. The two have different :-

The equation for a wave travelling in x-direction on a string is : y = (3 cm) sin [(pi cm^(-1)) x - (314)s^(-1)t] Then find acceleration of a particle at x = 6 cm at t = 0.11 sec-

The phase difference between two SHM y_(1) = 10 sin (10 pi t + (pi)/(3)) and y_(2) = 12 sin (8 pi t + (pi)/(4)) to t = 0.5s is

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

A wave is represented by the equation y=(0.001mm)sin[(50s^-10t+(2.0m^-1)x]

A particle is subjected to two simple harmonic motions given by x_(1) = 2.0sin (100 pi t) and x_(2) = 2.0sin (120pi t + pi //3) where, x is in cm and t in second. Find the displacement of the particle at (a) t = 0.0125 , (b) t = 0.025 .