`(sin52^(@)+cos38^(@))/(sin38^(@)+cos52^(@))`

(2sin38^(@))/(cos52^(@))

cos38^(@)cos52^(@)-sin38^(@)sin52^(@)=0

(sin18^(0))/(cos72^(0))+(sin22^(0))/(cos68^(@))-(cos38^(0)cos ec52^(0))/(tan18^(@)tan35^(@)tan60^(@)tan72^(@)tan55^(@))

sin38^(@)+sin22^(@)=sin82^(@)

Without using Trigonometric Tables evaluate the following :- (cos58^@)/(sin32^@)+(sin22^@)/(cos68^@)-(cos38^@ cosec52^@)/(tan18^@tan35^@tan60^@tan72^@tan55^@) .

Statement -1: sin52^(@)+sin78^(@)+sin50^(@)=4cos26^(@)cos39^(@)cos25^(@) Statement-2: If A+B+C=pi, then sinA+sin B+sinC=4cos""(A)/(2)cos""(B)/(2)cos""©/(2)

Statement -1: sin52^(@)+sin78^(@)+sin50^(@)=4cos26^(@)cos39^(@)cos25^(@) Statement-2: If A+B+C=pi, then sinA+sin B+sinC=4cos""(A)/(2)cos""(B)/(2)cos""(C)/(2)

Evaluate: (cos 58^@)/(sin 32^@)+(sin 22^@)/(cos 68^@)-(cos 38^@cosec 52^@)/(tan 18^@tan 35 ^@ tan 60^@tan 72^@tan 55^@) .

Show that : cos38^(@)cos52^(@)-sin38^(@)sin52^(@)=0