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Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is

A

`1`

B

`2`

C

`sqrt(2)`

D

`(1)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`V prop sqrt(1)`
`(V_(1))/(V_(2)) = sqrt((T_(1))/(T_(2))) = sqrt((2T)/(T)) = sqrt(2)`
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