A transverse periodic wave on a string with a linear mass density of `0.200 kg//m` is described by the following equation
`y = 0.05 sin(420t - 21.0 x)`
where `x` and `y` are in meters and `t` is in seconds.
The tension in the string is equal to :

Options

A. `32 N`
B. `42 N`
C. `66 N`
D. `80 N`

Answer

D

Explanation

`V_(omega) = (omega)/(k) = (420)/(21) = 20 :. V = sqrt((T)/(mu)) = 20 rArr T = (20)^(2)mu = 20^(2) xx 0.2 = 80N`