A `20 cm` long rubber string fixed at both ends obeys Hook's law. Intially when it is stretched to make its total length of `24 cm`, the lowest frequency resonance is `v_(0)`. It is further stretched to make its total length of `26 cm`. The lowest frequency of resonance will now be :

Options

A. the same as `v_(0)`
B. greter than `v_(0)`
C. lower than `v_(0)`
D. None of these

Answer

B

Explanation

As `T = (YA)/(20) 4 rArr v_(0) = (1)/(2 xx 24) sqrt((Ya)/(20).(4)/(mu)) ….(1)`
and `T' = (YA)/(20) 6 rArr v' = (1)/(2 xx 26) sqrt((Ya)/(20).(6)/(mu)) ….(2)`
`:. (v')/(v_(0)) = (24)/(26)sqrt((6)/(4))`
`:. v' gt v_(0)`