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The particles displacement in a wave is ...

The particles displacement in a wave is given by
`y = 0.2 xx 10^(-5) cos (500 t - 0.025 x)`
where the distances are measured in meters and time in seconds. Now

A

wave velocity is `2 xx 10^(4)ms^(-1)`

B

particles velocity is `2 xx 10^(4)ms^(-1)`

C

initial phase difference is `(pi)/(2)`

D

wavelength of the wave is `(80pi)m`

Text Solution

Verified by Experts

The correct Answer is:
A, D

Comparing with `y = A cos (omegat - kx)`
`omega = 500s^(-1), k = 0.025 m^(-1)`,
`v = (500)/(0.025) = 2 xx 10^(4)m//s , lambda = (2pi)/(0.025) = 80 pi m`
`y = A cos (omegat - kx)`
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