When two progressive waves `y_(1) = 4 sin (2x - 6t)` and `y_(2) = 3 sin (2x - 6t - (pi)/(2))` are superimposed, the amplitude of the resultant wave is

Answer

A

Explanation

`V = omegasqrt(A^(2) - y^(2))`
`V_(P) = 2pifsqrt(A^(2) - y^(2))`
`V_(P) = 2pi((V)/(lambda)) sqrt(A^(2) - y^(2)) = (2pi)/(0.5) xx 0.1 sqrt((0.1)^(2) - (0.05)^(2))`
`V_(P) = (sqrt(3)pi)/(50) j m//s`