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How are xenon fluorides XeF(2),XeF(4) an...

How are xenon fluorides `XeF_(2),XeF_(4)` and `XeF_(6)` obtained?

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The correct Answer is:
All these xenon fluorides are prepared by direct reaction between `Xe` and `F_(2)` under different conditions as shown below :
`underset(("Excess"))(Xe(g)+) F_(2)(g) overset(673 K, 1 "bar")to XeF_(2)(s)`
`underset((1:5 "ratio"))(Xe(g)+) 2F_(2)(g) overset(873 K, 7 "bar")to XeF_(4)(s)`
` `underset((1:20 "ratio"))(Xe(g)+) 3F_(2)(g) overset(573 K, 60-70 "bar")to XeF_(6)(s)`
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