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Statement-1 :IO(3)^(-) oxidises I^(-) to...

Statement-1 :`IO_(3)^(-)` oxidises `I^(-)` to `I_(2)` in acidic medium.
Statement-2 : `HIO_(3)` is formed by oxidation of `I_(2)` with concentrated `HNO_(3)`.

A

Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-6

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

Verified by Experts

The correct Answer is:
B
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KMnO_(4) oxidises I^(-) to I_(2) in acidic medium. The equivalent weight of KMnO_(4) is :

Write the oxidation product when XeO_(3) oxidises I^(-) in acidic medium.

I^(-) reduces IO_(3)^(-) and I_(2) and itself oxidised to I_(2) in acidic medium. Thus, final reaction is

IO_(3)^(-)+I^(-)+H^(+) to

Statement -1 I_(2) +I to I_(3) in above .I_(2) is lewis base and Satement -2 Electron pair acceptor is lewis base