Home
Class 12
CHEMISTRY
Arrange the XeF(2),XeF(4),XeF(6) in decr...

Arrange the `XeF_(2),XeF_(4),XeF_(6)` in decreasing order of Xe-F bond length, give reason also.

Text Solution

Verified by Experts

The correct Answer is:
`XeF_(2)ltXeF_(4)ltXeF_(6)`
`2.00 Å 1.94 Å 1.89 Å` (due to increase in number of fluorine atoms on xenon atom)
Promotional Banner

Topper's Solved these Questions

  • P BLOCK ELEMENTS

    RESONANCE|Exercise Exercise 2 part-2|42 Videos
  • P BLOCK ELEMENTS

    RESONANCE|Exercise Exercise 2 part-3|6 Videos
  • P BLOCK ELEMENTS

    RESONANCE|Exercise Exercise 1 part-3|10 Videos
  • NUCLEAR CHEMISTRY

    RESONANCE|Exercise STAGE-II|1 Videos
  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE|Exercise PART - III : OLYMPIAD PROBLEMS (PREVIOUS YEARS) STAGE - V (INTERNATIONAL CHEMISTRY OLYMPIAD (IChO)) Problem 3|8 Videos

Similar Questions

Explore conceptually related problems

XeF_(6) on hydrolysis gives

XeF_(4) and XeF_(6) are expected to be

XeF_(4)+O_(2)F_(2) to

XeF_(4)+O_(2)F_(2) to

In XeF_(2),XeF_(4)" and "XeF_(6), the number of the lone pairs of Xe respectively are

In XeF_(2),XeF_(4) and XeF_(6)(g) the number of lone pairs on Xe respectively are :