A certain compound (X) shows the following reactions.
(i)When Kl is added to an aqueous suspension of (X) containing dilute HCl, iodine is liberated.
(ii)When the paste of (X) in water is heated with acetone, a product of anesthetic use is obtained.
(iii)When `CO_(2)` is passed through an aqueous suspension of (X) the turbidity transforms to a precipitate.
Identify (X) and write down chemical equations for the step (i),(ii) & (iii)

Answer

To identify the compound (X) and write down the chemical equations for the given reactions, we can analyze each reaction step by step.

### Step 1: Analyze Reaction (i)
**Reaction:** When KI is added to an aqueous suspension of (X) containing dilute HCl, iodine is liberated.

**Analysis:**
- The liberation of iodine (I2) suggests that (X) is likely a compound that can oxidize iodide ions (I-) from KI to iodine (I2).
- A common compound that fits this description is calcium hypochlorite (Ca(OCl)2), which can release chlorine in the presence of acid, leading to the oxidation of iodide ions.

**Chemical Equation:**
\[ \text{Ca(OCl)}_2 + 2 \text{KI} + 2 \text{HCl} \rightarrow \text{CaCl}_2 + 2 \text{I}_2 + 2 \text{KCl} + 2 \text{H}_2\text{O} \]

### Step 2: Analyze Reaction (ii)
**Reaction:** When the paste of (X) in water is heated with acetone, a product of anesthetic use is obtained.

**Analysis:**
- The product of anesthetic use suggests the formation of a ketone or an ester.
- Calcium hypochlorite (Ca(OCl)2) can react with acetone to form chloroform (CHCl3), which is known to have anesthetic properties.

**Chemical Equation:**
\[ \text{Ca(OCl)}_2 + \text{acetone} \rightarrow \text{CHCl}_3 + \text{other products} \]

### Step 3: Analyze Reaction (iii)
**Reaction:** When CO2 is passed through an aqueous suspension of (X), the turbidity transforms to a precipitate.

**Analysis:**
- The formation of a precipitate upon passing CO2 suggests that (X) is a basic compound that reacts with CO2 to form a carbonate.
- Calcium hydroxide (Ca(OH)2) can react with CO2 to form calcium carbonate (CaCO3), which is insoluble in water and would cause turbidity to settle as a precipitate.

**Chemical Equation:**
\[ \text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 \downarrow + \text{H}_2\text{O} \]

### Conclusion
Based on the analysis of the reactions, the compound (X) is identified as **Calcium Hydroxide (Ca(OH)2)**.

### Summary of Reactions:
1. **Reaction (i):**
\[ \text{Ca(OCl)}_2 + 2 \text{KI} + 2 \text{HCl} \rightarrow \text{CaCl}_2 + 2 \text{I}_2 + 2 \text{KCl} + 2 \text{H}_2\text{O} \]

2. **Reaction (ii):**
\[ \text{Ca(OCl)}_2 + \text{acetone} \rightarrow \text{CHCl}_3 + \text{other products} \]

3. **Reaction (iii):**
\[ \text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 \downarrow + \text{H}_2\text{O} \]