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The vander waals constant for HCI are a ...

The vander waals constant for `HCI` are `a = 371.843 Kpa.dm^(6)mol^(-1)` and `b = 40.8 cm^(3) mol^(-1)` find the critical constant of this substance.

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The critical pressure, `P_(c) = (a)/(27b^(2)) = (371.843 xx 10^(3))/(27xx(40.8)^(2)xx10^(-6)) = (371.843 xx 10^(9))/(27xx(40.8)^(2)) = 8.273 xx 10^(6) Pa = 8.273 Mpa`
The critical pressure, `T_(c) = (8a)/(27Rb)`
`R = 8.314 Kpa dm^(3) K^(-1) mol^(-1)`
`T_(c) = (8a)/(27Rb) = (8 xx 371.843)/(8.314 xx 27 xx40.8 xx 10^(-3)) = 324.79 = 324.8 K`
The critical volume, `V_(c) = 3b = 3 xx 40.8 = 122.4 cm^(3)`
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