One litre gas at `400K` and `300atm` pressure is compressed to a pressure of `600 atm` and `200K`. The compressibility factor is changed from `1.2 to 1.6` respectively. Calculate the final volume of the gas.

Answer

`(1)/(3)litre`

Explanation

`Z_(i) = (P_(1)V_(1))/(RT_(1))` and `Z_(2) = (P_(2)V_(2))/(RT_(2))`
`(Z_(1))/(Z_(2)) = (P_(1))/(P_(2)) xx (T_(2))/(T_(1)) xx (V_(1))/(V_(2)) rArr V_(2) = (1)/(3) litre`