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At low pressures (for 1 mole), the van d...

At low pressures (for 1 mole), the van der Waal's equation is written as `[P+(a)/(V^(2))]V=RT`
The compressibility factor is then equal to :

A

`(1-(a)/(RTV))`

B

`(1-(RTV)/(a))`

C

`(1+(a)/(RTV))`

D

`(1+(RTV)/(a))`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P +(a)/(V^(2)) (V) = RT rArr PV +(a)/(V) = RT rArr (PV)/(RT) = 1 - (a)/(VRT)`
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