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The threshold frequency nu(0) for a meta...

The threshold frequency `nu_(0)` for a metal is `6xx10^(14) s^(-1)`. Calculate the kinetic energy of an electron emitted when radiation of frequency `nu=1.1xx10^(15) s^(-1)` hits the metal.

Text Solution

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`K.E.=1/2 m_(e)v^(2)=h(nu-nu_(0))`
`:. K.E.=(6.626xx10^(-34))(1.1xx10^(15)-6xx10^(14))`
`:. K.E.=(6.626xx10^(-34))(5xx10^(14))`
`=3.313xx10^(-19) J`
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