Calculate the total spin and magnitic moment for atoms having atomic numbers `7`, `24`, `34` and `36`.

Explanation

The electronic configuration are
`{:(._(7)N,:,1s^(2)","2s^(2) 2p^(3),"unpaired electron" =3),(._(24)Cr,:,1s^(2)","2s^(2) 2p^(6), 3s^(2) 3p^(6) 3d^(5)","4s^(1),"unpaired electron" =6),(._(36)Kr,:,1s^(2)","2s^(2) 2p^(6)"," 3s^(2) 3p^(6) 3d^(10)"," 4s^(2) 4p^(6),"unpaired electron" =0):}`
`:.` Total spin for an atom `= +- 1//2 xx` no. of unpaired electron
For `_(7)N`, it is `=+- 3//2`, For `_(24)Cr`, it is `=+- 3`, For `_(36)Kr`, it is `=0`
Also magnetic moment `=sqrt(n(n+2))`
For `_(7)N`, it is `=sqrt(15)`, For `_(24)Cr`, it is `=sqrt(48)`, For `_(36)Kr`, it is `=sqrt(0)`