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The de Broglie wavelength of an electron...

The de Broglie wavelength of an electron moving in a circular orbit is `lambda` . The minimum radius of orbit is :

A

`lambda/pi`

B

`lambda/(2pi)`

C

`lambda/(4pi)`

D

`lambda/(3pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
We know `2 pir=nlambda`
For minimum radius `n=1`
`2pir_("min")=lambda`
`r_("min")=lambda/(2pi)`
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