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.(92)^(235)U decays with emission of alp...

`._(92)^(235)U` decays with emission of `alpha` and `beta`- particles to form ultimately `._(82)^(207)Pb`. How many `alpha` and `beta`-particles are emitted per atom of Pb produced?

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The correct Answer is:
`._(92)^(235)U rarr ._(82)^(207)Pb+7_(2)^(4)He+4_(-1)^(0)e (4n+ 3 "series")`
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