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The speed of a certain proton is 0.45 Mm...

The speed of a certain proton is `0.45 Mms^(-1)`. If the uncertainty in its momentum is to `b` reduced to `0.0100` percent, what incertainty in its location must be tolerated?

A

`0.60 nm`

B

`0.72 nm`

C

`0.80 nm`

D

`0.70 nm`

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltap ~~0.010 perce of p_(0)=p_(0)xx(1.00xx10^(-4))=m_(p)vxx(1.00xx10^(-4))(p_(0)=m_(p)v)`
`Deltaq~~(h)/(2Deltap)~~(1.055xx10^(-34) Js)/((2)xx(1.673xx10^(-27) kg)xx(4.5xx10^(5) ms^(-1))xx(1.00xx10^(-4)))~~7.01xx10^(-10) m, "or" 0.70 nm`
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