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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in `2s`-orbital is

A

`+1/2h/(2pi)`

B

zero

C

`h/(2pi)`

D

`sqrt(2) h/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
Orbital angular momentum `=sqrt(l(l+1))(h)/(2pi)=0` (since l=0 for s orbital).
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