For an electron, with n=3 has only one radial node.
The orbital angular momentum of the electron will be :

Options

A. `0`
B. `sqrt(6) h/(2pi)`
C. `sqrt(2) h/(2pi)`
D. `3(h/(2pi))`

Answer

C

Explanation

Number of radial nodes `=nl-1=1, n=3 :. l=1`.
Orbital angular momentum `=sqrt(l(l+1)) (h)/(2pi)=sqrt(2) (h)/(2pi)`