The conductivity of 0.001 M acetic is ` 4 xx 10^(-5)S//cm.` Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic is 390 S `cm^(2)//mol.`

The conductivity of 0.001 M actic acid is 4 xx 10^(-5) S //cm . Calculate the dissociation constant acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm^(2) // mol.

The conductivity of 0.001M acetic acid is 4 times 10^-8 S//cm . Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm^2//mol .

The conductivity of 0.001M acetic acid is 4X10^(-2)S//m . Calculate the dissociation constant of acetic acid if lambda_m^@ for acetic acid is 390Scm^2mol^(-1) .

Calculating the value of dissociation constant of weak electrolyte: The conductivity of 0.001028 mo L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dssociation constatnt if Lambda_(m)^(0) for acetic acid is 390.5 S cm^(2) mol^(-1) . Strategy: We can determine the value of the dissociation constant for week electrolytes once we know the Lambda_(m)^(0) and Lambda_(m) at any given concentration C .

Conductivity of 0.00241 M acetic acid solution is 7.896 xx 10^(-5) S cm^(-1) . Calculate its molar conductivity in this solution. If wedge_(M)^(@) for acetic acid be 390.5 S cm^(2) mol^(-1) , what would be its dissociation constant?

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^(-5) S cm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic is 390.5 S cm^(2) mol^(-1) ?