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In the photoelectric effect the eletrons...

In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by :
`hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE`
If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy
i.e `hv_(0)`
`:.(1)/(2)m u^(2)=hv-hv_(0)`
A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as :

The number of photoelectrons emitted depends upon :

A

The intensity of the incident radiation

B

The frequency of the incident radiation

C

The product of intensity and frequency of incident radiation

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
The number of photoelectrons emitted depends on the intensity or brightness of incident radiation.
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In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by : hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy i.e hv_(0) :.(1)/(2)m u^(2)=hv-hv_(0) A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as : A beam of white light is dispersed into its wavelenght components of potassium metal. What of the electron emitted by the different light component ?

In the photoelectric effect the eletrons are emiited intantaneously from a given matal plate when it is irradiated with radiation of frequency equal to or greater then some minimum ferquency, is called the threshold frequency.According to Planck's idea, light may be considered to be made up discrete particles called photons.Each photon carries energy equal ti hv.When this photon cllides with the electron of the metal, the electron acquires energy of the emitted electron is given by : hv=K.E_("maximum")+PE=(1)/(2)m u^(2)+PE If the incident rediation is of threshold frequency the electron will be emitted without any kinetic energy i.e hv_(0) :.(1)/(2)m u^(2)=hv-hv_(0) A plot of kinetic energy of the emitted electron versus frequency of the incident radiation yields a straight line given as : A laser producting monochromatic lights of different wavelenght is uesd to eject electrons from the sheet of glod having threshold frequency 6.15xx10^(14)s^(-1) Which of the following incident rediation will be suitable for the ejecting of electrons ?

According to Max Planck energy of photon is

The momentum of a photon having energy equal to the rest energy of an electron is

Assertion: Photoelectric effect proves the particle nature of light. Reason: Photoemission starts as soon as light is incident on the metal surface, provided frequency of incident light is greater than or equal to the threshold frequency.

When photons of energy hv fall on a metal plate of work function ' W_(0) ' , photoelectrons of maximum kinetic energy 'K' are ejected. If the frequency of the radiation is doubted, the maximum kinetic energy of the ejected photoelectrons will be

A metal is irradiated with light of frequency 3.2xx10^(16)Hz . The ejected photoelectron has kinetic energy (3)/(4) the of energy of absorbed photon. The threshold frequency orf the metal would be :

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