The hydrogen -like species `Li^(2+)` is in a spherically symmetric state `S_(1)` with one node. Upon absorbing light , the ion undergoes transition to a state `S_(2)`. The state `S_(2)` has one radial node and its energy is equal is to the ground state energy of the hydrogen atom.
The orbital angular momentum quantum number of the state `S_(2)` is

Options

A. `0`
B. `1`
C. `2`
D. `3`

Answer

B

Explanation

For state `S_(2)`
No. of radial node `=1=n-l-1` ….(ep. -1)
Energy of `S_(2)` state =energy of `e^(-)` in lowest state of H-atom
`=-13.6 eV//atom=-13.6(3^(2)/n^(2)) eV//atom`
`n=3`.
put in equation (1) `l=1`
so, orbital `rArr 3p ("for" S_(2) "state")`